1、 应用场景：通常在开发流上都会保留本版本或历史版本的多个bulid，若需要获取目录中（目录中除了build还有很多其他名称不一样的文件）最新的build安装该如何写脚本实现呢？而且通常build的命名中都会有依次增加的version号，该如何实现脚本可每日重复使用呢？
2、实现思路：1>处理文件名称，定义一个常量文件名，将文件名中的变化的version号用*代替；
2>给定已知的目录，获取给目录下所有的子文件，然后将按*分割，依次匹配子文件的文件名和被分割的这两部分名称。
3、代码如下：
'Description:fetch new build
'author:Alan
'Date:2014-10-31
Function strFetchBuild(path,filename)
Dim i,j,FileNames,splits,flag
FileNames = aGetAllFillname(path)
If IsEmpty(FileNames)=false and IsArray(FileNames) Then
'whether the filename format is right or not
If Instr(filename,"*")>0 Then
'according to * split filename
splits=Split(filename,"*")
For i=0 To UBound(FileNames)
flag=0
' If each split block are matched, then return name
For j= 0 To UBound(splits)
If Instr(FileNames(i),splits(j))>0 Then
flag=flag+1
End If
Next
If flag = UBound(splits)+1 Then
strFetchBuild = path & "\" & FileNames(i)
Else
'If didn't match to the end of the loop, then exit function
If i=UBound(FileNames)+1 Then
Log.Error("The file:" & filename & " not found.")
strFetchBuild = ""
Exit Function
End If
End If
Next
Else
Log.Error("The file name format" &"'" & filename & "'"&" is not right.")
strFetchBuild = ""
Exit Function
End If
Else
Log.Error("The path:" & path & " not exists.")
strFetchBuild = ""
End If
End Function 
