根据时间变化绘制的，即时的，或许可以用chart图表控件，百度会出现微软网站的资料。
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sin曲线永远是哪个样子，你是怎么变化？一般的移动，可以用offset控制向左平移，右边则增加点，看上去应该是在移动
Dim Points1(30) As Point
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Timer1.Enabled = True
Timer1.Interval = 200
For i = 0 To 30
Points1(i) = New Point(i * 45, Math.Sin(i) * (PictureBox1.Height - 50) / 9)
Points1(i).Offset(-450, Math.Abs(Points1(i).Y - (PictureBox1.Height - 50) / 9) * 3.55 + 43)
Next
End Sub
Private Sub Timer1_Tick(ByVal sender As Object, ByVal e As System.EventArgs) Handles Timer1.Tick
Static j As Long
j = j + 1
PictureBox1.Image = x_y(PictureBox1, j)
End Sub
Private Function x_y(ByVal pic As PictureBox, ByVal x As Long) As Bitmap
Dim b As New Bitmap(pic.Width, pic.Height)
Dim g As Graphics = Graphics.FromImage(b)
Dim c
Dim j
g.Clear(Color.YellowGreen)
Dim p As New Pen(Color.WhiteSmoke)
p.EndCap = Drawing2D.LineCap.ArrowAnchor
g.DrawLine(p, 20, pic.Height - 20, 20, 10)
g.DrawLine(p, 20, pic.Height - 20, pic.Width - 20, pic.Height - 20)
Dim i As Double
Dim bs As New SolidBrush(Color.Red)
Dim po As New Point
g.DrawString(-2, Me.Font, bs, 12, pic.Height - 18)
po.X = 0
po.Y = pic.Height - 45
For i = -1.6 To 4 Step 0.4
g.DrawString(Math.Round(i, 1), Me.Font, bs, po.X, po.Y)
g.DrawLine(p, po.X + 18, po.Y + 5, po.X + 20, po.Y + 5)
Dim p1 As New Pen(Color.Blue)
p1.DashStyle = Drawing2D.DashStyle.Dash
g.DrawLine(p1, po.X + 28, po.Y + 5, pic.Width - 20, po.Y + 5)
po.Y -= (pic.Height - 50) / 9
Next
po.X = 20
po.Y = pic.Height - 20
For c = 0 To 14400 Step 1200
If (c / 1200) 0 Then
g.DrawString((c / 1200) + x, Me.Font, bs, po.X - j, po.Y + 5)
End If
g.DrawLine(p, po.X, po.Y + 2, po.X, po.Y)
po.X += (pic.Width - 50) / 12
Next
For i = 0 To Points1.Count - 1
Points1(i).Offset(45, 0)
Next
If x Mod 6 = 0 Then
For i = 0 To Points1.Count - 1
Points1(i).Offset(-270, 0)
Next
End If
g.DrawCurve(Pens.Red, Points1)
'For i = 0 To Points1.Count - 1
'g.DrawString(Math.Sin(i), Me.Font, Brushes.Red, Points1(i))
'Next
Return b
End Function
为什么我的不是?
Dim pi
pi = 3.1415926
Dim a
a = 30
Text1.Text = Sin(a * pi / 180)
VB系统的坐标原点在左上角，X轴的正方向是水平向右，而Y轴的正方向是垂直向下。所以，要绘制三角函数的曲线，自己可以通过改变点坐标的方法来实现，当然，VB.NET提供了相应的方法可以来实现坐标变换，也可以通过VB.Net的Graphics类提供的平移、旋转等转换来实现。
下面是我通过自己变换实现的示例，提供参考；我的环境是VB.NET 2010
Imports System.Math
Public Class Form1
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
'1，获得一个Graphics对象
Dim MyGraphics As Graphics
MyGraphics = PictureBox1.CreateGraphics
'2，定义一个Pen对象，用于绘制图形（轮廓线）
Dim MyPen As New Pen(Color.Black, 1)
'3，定义一个Brush对象，用于填充图形（如果需要填充的话）
Dim MyBrush As New SolidBrush(Color.Orange)
MyGraphics.DrawLine(MyPen, 0, 200, 700, 200)
End Sub
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
'1，获得一个Graphics对象
Dim MyGraphics As Graphics
MyGraphics = PictureBox1.CreateGraphics
'2，定义一个Pen对象，用于绘制图形（轮廓线）
Dim MyPen As New Pen(Color.Black, 1)
'3，定义一个Brush对象，用于填充图形（如果需要填充的话）
Dim MyBrush As New SolidBrush(Color.Orange)
'声明横向和纵向比例变量
Dim Heng As Integer = 20
Dim Zong As Integer = 50
'先获得正弦值，保存到点坐标数组
Dim MyPoints(700) As Point
Dim i As Integer
For i = 0 To 700
MyPoints(i) = New Point(i * Heng, 200 + Sin(i) * Zong)
Next
'采用绘制光滑线连接点的方式绘制曲线
MyGraphics.DrawCurve(MyPen, MyPoints)
End Sub
End Class
显示的效果图：
