这篇文章主要介绍“C++怎么移除元素”，在日常操作中，相信很多人在C++怎么移除元素问题上存在疑惑，小编查阅了各式资料，整理出简单好用的操作方法，希望对大家解答”C++怎么移除元素”的疑惑有所帮助！接下来，请跟着小编一起来学习吧！
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Given an array nums and a value val, remove all instances of that value in-place and return the new length.
Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
The order of elements can be changed. It doesn"t matter what you leave beyond the new length.
Example 1:
Given nums = [3,2,2,3], val = 3,
Your function should return length = 2, with the first two elements of nums being 2.
It doesn"t matter what you leave beyond the returned length.
Example 2:
Given nums = [0,1,2,2,3,0,4,2], val = 2,
Your function should return length =
5
, with the first five elements of
nums
containing
0
,
1
,
3
,
0
, and 4.
Note that the order of those five elements can be arbitrary.
It doesn"t matter what values are set beyond the returned length.
Clarification:
Confused why the returned value is an integer but your answer is an array?
Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.
Internally you can think of this:
// nums is passed in by reference. (i.e., without making a copy)
int len = removeElement(nums, val);
// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
print(nums[i]);
}
这道题让我们移除一个数组中和给定值相同的数字，并返回新的数组的长度。是一道比较容易的题，只需要一个变量用来计数，然后遍历原数组，如果当前的值和给定值不同，就把当前值覆盖计数变量的位置，并将计数变量加1。代码如下：
class Solution {
public:
int removeElement(vector& nums, int val) {
int res = 0;
for (int i = 0; i < nums.size(); ++i) {
if (nums[i] != val) nums[res++] = nums[i];
}
return res;
}
}; 到此，关于“C++怎么移除元素”的学习就结束了，希望能够解决大家的疑惑。理论与实践的搭配能更好的帮助大家学习，快去试试吧！若想继续学习更多相关知识，请继续关注创新互联网站，小编会继续努力为大家带来更多实用的文章！
